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DefaultDict Tutorial

Problem link : https://www.hackerrank.com/challenges/defaultdict-tutorial/problem

Difficulty : Easy

Tip

1. Problem suggest to use defaultdict(), however, it seems that just using list is better way
2. One loop for list m, as per each m, to find index of m from list n
1. this way is better to know index from list n

Solution

a = list(map(int, input().split())) n = a[0] m = a[1] ns = [] ms = [] for _ in range(n): ns.append(input()) for _ in range(m): ms.append(input()) for i in range(len(ms)): indices = [] c = ms[i] for j in range(len(ns)): if c == ns[j]: indices.append(j+1) if len(indices) == 0: print(-1) else: print(*indices, sep=' ')