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No Idea!

Tip

• Please utilize set() to check that n integers is in set A(or B)
• Actually, the numbers(n and m) is not matter for problem
• As we can split and count each integer from input(), like below
• input().split()
• Create list from n integers
• Create set A and set B
• check each item in list is in set A or set B

Solution

# Enter your code here. Read input from STDIN. Print output to STDOUT n, m = input().split() n = int(n) m = int(m) target_items = input().split() targets = [int(target_items[i]) for i in range(len(target_items))] a_items = input().split() b_items = input().split() setA = set([int(a_items[i]) for i in range(len(a_items))]) setB = set([int(b_items[i]) for i in range(len(b_items))]) cntHappy = 0 for t in targets: if t in setA: cntHappy += 1 if t in setB: cntHappy -= 1 print(cntHappy)